AP Bio Lab
Home
Learn
Flashcards
Practice
Mock Exam
Dashboard
About
Sign out
AP Bio Lab
Practice
MCQ
Question 1
Score: 0/0
Natural Selection ·
change
Question 1
Hardy-Weinberg calculation for a trait
Quantity
Value
Frequency of recessive phenotype (aa)
0.09
Population size
10,000
Assuming Hardy-Weinberg equilibrium, how many individuals are expected to be heterozygous carriers?
A.
q² = 0.09, so q = 0.30 and p = 0.70; heterozygotes = 2pq = 0.42, so 0.42 × 10,000 = 4,200 carriers.
B.
0.09 × 10,000 = 900 carriers, equal to the recessive phenotype count.
C.
p = 0.09 and q = 0.91; carriers = 2(0.09)(0.91) ≈ 1,638.
D.
Cannot be determined without knowing the dominance relationship.
Next question
